Check solubility of the products, to determine if there is a reaction. Assume all reactions occur in water or in contact with water. You can ask a new question or browse more chemistry questions. }
For Free. Silver nitrate and Rubidium chloride Overall Equation:AgNO3 (aq) + RbCl(aq) --> AgCl(s) + RbNO3 (aq)Total Ionic Equation:Ag+ (aq) + NO3- (aq) + Rb+(aq) + Cl-(aq) -> AgCl(s) + Rb+(aq) + NO3- (aq)Net Ionic Equation:Ag+ (aq) + Cl-(aq) -> AgCl(s) 2. mercury (I) nitrate and hydrochloric acidOverall Equation:Hg2(NO3)2 (aq) + 2 HCl (aq) --> Hg2Cl2 (s) + 2 HNO3 (aq)Total Ionic Equation:Hg22+(aq) + 2 NO3- (aq) + 2 H+(aq) + 2 Cl- (aq) --> Hg2Cl2 (s) + 2 H+ (aq) + 2 NO3-(aq)Net Ionic Equation:Hg2+(aq) + 2 Cl- (aq) --> Hg2Cl2 (s) 3. calcium chloride and sodium carbonateOverall Equation:CaCl2 (aq) + Na2CO3 (aq) -> 2 NaCl(aq) + CaCO3 (s)Total Ionic Equation:Ca2+(aq)+ 2 Cl- (aq) + 2 Na+ (aq)+ CO32- (aq) -> 2 Na+(aq) + 2 Cl-(aq) + CaCO3 (s)Net Ionic Equation:Ca2+(aq) + CO32- (aq) -> CaCO3 (s)4. magnesium nitrate and calcium chloride Overall Equation:Mg(NO3)2 (aq) + CaCl2 (aq) -> Ca(NO3)2 (aq) + MgCl2 (aq)Total Ionic Equation:Mg2+ (aq) + 2 NO3- (aq) + Ca2+ (aq) + 2 Cl- (aq) --> Ca 2+(aq) + 2 NO3- (aq) + Mg2+(aq) + 2 Cl- (aq)Net Ionic Equation:No Reaction5. potassium sulfate and barium chloride Overall Equation:K2SO4 (aq) + BaCl2 (aq) --> BaSO4 (s) + 2 KCl (aq)Total Ionic Equation:2 K+ (aq)+ SO42- (aq) + Ba2+ (aq) + 2 Cl- (aq) --> BaSO4 (s) + 2 K+(aq)+ 2 Cl- (aq)Net Ionic Equation:SO42- (aq) + Ba2+ (aq) -> BaSO4 (s)More problems- AP Chemistry, Overall Equation:AgNO3 (aq) + RbCl(aq) --> AgCl(s) + RbNO3 (aq), 2. mercury (I) nitrate and hydrochloric acid, Overall Equation:CaCl2 (aq) + Na2CO3 (aq) -> 2 NaCl(aq) + CaCO3 (s), Overall Equation:Mg(NO3)2 (aq) + CaCl2 (aq) -> Ca(NO3)2 (aq) + MgCl2 (aq), Overall Equation:K2SO4 (aq) + BaCl2 (aq) --> BaSO4 (s) + 2 KCl (aq), 2) calcium hydroxide + hydrosulfuric acid , 4) lead (II) hydroxide + carbonic acid , Insoluble Weak Acid Insoluble liquid. (aq) Mn (aq) + CO,(g). If 13.45 g of copper (II) chloride react, what is the maximum amount of precipitate that could be formed? Quantum Physics: Heres Why Movies Always Get It Wrong, What Are The Different Atomic Models? google_ad_client = "pub-0644478549845373";
What Are Single Replacement And Double Replacement Reactions? The complete ionic equation shows each of the aqueous compounds as separate ions. And also, on PbCl. When aqueous Lead nitrate (Pb(NO3)2) Because lead is a heavy metal, you should be extremely careful in handling lead containing solutions. Question: What is the correct balanced complete ionic equation for the reaction of lead (II) nitrate with potassium chloride? to decide limiting reagent in reactions, Sandmeyer reactions of benzenediazonium chloride, Calcium bromide and sodium carbonate reaction, Lead sulfide and Lead (II) chloride will precipitate. 6-(&A!54-.&h Solid lead nitrate and aqueous sodium chloride reaction, Aqueous lead nitrate and solid sodium chloride reaction, Physical and chemical properties changes during the reaction, Health, safety and environmental impacts due to combustion of ethanol, Ask your chemistry questions and find the answers, What is the limiting reagent and how reaction, Chlorine's oxidation number in NaCl is -1. For example, the balanced chemical equation for the reaction of potassium chloride with lead nitrate is: Now, we must identify the physical state of each participant reactant and product in the equation. 4. magnesium nitrate and calcium chloride. }
(2 points) Molecular: Complete ionic: Net ionic: 14. To write an ionic equation, we will now need to break down the aqueous compounds into their component ions. For this purpose, we make use of the periodic table and the solubility table. Sodium chloride and lead II nitrate
Molecular Equation: 2NaCl(aq) + Pb(NO3)2(aq) ( PbCl2(s) + 2NaNO3(aq)
Complete Ionic Equation:
2Na+(aq) + 2Cl-(aq) + Pb2+(aq) + 2NO3-(aq) ( PbCl2(s) + 2Na+(aq) + 2NO3-(aq)
Particulate drawing:
Net Ionic Equation: 2Cl-(aq) + Pb2+(aq) ( PbCl2(s)
Sodium carbonate and Iron II chloride
Molecular Equation: Na2CO3(aq) + FeCl2(aq) ( FeCO3(s) + 2NaCl(aq)
Complete Ionic Equation: 2Na+(aq) + CO32-(aq) + Fe2+(aq) + 2Cl-(aq) ( FeCO3(s)
Particulate drawing:
Net Ionic Equation: CO32-(aq) + Fe2+(aq) ( FeCO3(s)
Magnesium hydroxide and hydrochloric acid
Molecular Equation: Mg(OH)2(aq) + 2HCl(aq) ( MgCl2(aq) + 2H2O(l)
Complete Ionic Equation:
Mg2+(aq) + 2OH-(aq) + 2H+(aq) + 2Cl-(aq) ( Mg2+(aq) + 2Cl-(aq) + 2H2O(l)
Particulate drawing:
Net Ionic Equation: 2OH-(aq) + 2H+(aq) ( 2H2O(l)
(your final answer would be: OH-(aq) + H+(aq) ( H2O(l))
Potassium chromate and calcium chloride
Molecular Equation: K2(CrO4)(aq) + CaCl2(aq) ( 2KCl(aq) + Ca(CrO4)aq)
Complete Ionic Equation:
2K+(aq) + CrO42-(aq) + Ca2+(aq) + 2Cl-(aq) ( 2K+(aq) + 2Cl-(aq) + Ca 2+(aq) + CrO42-(aq)
Particulate drawing:
Net Ionic Equation: NA all spectator ions
Ammonium phosphate and zinc nitrate
Molecular Equation: 2(NH4)3PO4(aq) + 3Zn(NO3)2(aq) (6NH4NO3(aq) + Zn3(PO4)2(s)
Complete Ionic Equation:
6NH4+(aq) + 2PO43-(aq) + 3Zn2+(aq) + 6NO3-(aq) ( 6NH4+(aq) + 6NO3-(aq) + Zn3(PO4)2(s)
Particulate drawing:
Net Ionic Equation: 2PO43-(aq) + 3Zn2+(aq) ( Zn3(PO4)2(s)
Lithium hydroxide and barium chloride
Molecular Equation: 2LiOH(aq) + BaCl2(aq) ( 2LiCl(aq) + Ba(OH)2(s)
Complete Ionic Equation: 2Li+(aq) + 2OH-(aq) + Ba2+(aq) + 2Cl-(aq) ( 2Li+(aq) + 2Cl-(aq) + Ba(OH)2(aq)
Particulate drawing:
Net Ionic Equation: 3OH-(aq) + Ba2+(aq) ( Ba(OH)3(s)
Sodium carbonate and hydrochloric acid produces sodium chloride, carbon dioxide and water
Molecular Equation: Na2CO3(aq) + 2HCl(aq) ( 2NaCl(aq) + CO2(g) + H2O(l)
Complete Ionic Equation: 2Na+(aq) + CO32-(aq) + 2H+(aq) + 2Cl-(aq) ( 2Na+(aq) + 2Cl-(aq) + CO2(g) + H2O(l)
Particulate drawing:
Net Ionic Equation: CO32-(aq) + 2H+(aq) ( CO2(g) + H2O(l)
Magnesium nitrate and sodium chromate
Molecular Equation: Mg(NO3)2(aq) + Na2CrO4(aq) ( 2NaNO3(aq) + MgCrO4(s)
Complete Ionic Equation:
Mg2+(aq) + 2NO3-(aq) + 2Na+(aq) + CrO42-(aq) ( 2Na+(aq) + 2NO3-(aq) + MgCrO4(s)
Particulate drawing:
Net Ionic Equation: Mg2+(aq) + CrO42-(aq) ( MgCrO4(s)
Iron III chloride and magnesium metal
Molecular Equation: 2FeCl3(aq) + 3Mg(s) ( 3MgCl2(aq) + 2Fe(s)
Complete Ionic Equation:
2Fe3+(aq) + 6Cl-(aq) + 3Mg(s) ( 3Mg2+(aq) + 6Cl-(aq) + 2Fe(s)
Particulate drawing:
Net Ionic Equation: 2Fe3+(aq) + 3Mg(s) ( 3Mg2+(aq) + 2Fe
Barium Bromide and sodium sulfate
Molecular Equation: BaBr2(aq) + Na2SO4(aq) ( BaSO4(s) + 2NaBr(aq)
Complete Ionic Equation: Ba2+(aq) + 2Br-(aq) + 2Na+(aq) + SO42-(aq) ( BaSO4(s) + 2Na+(aq) + 2Br-(aq)
Particulate drawing:
Net Ionic Equation: Ba2+(aq) + SO42-(aq) ( BaSO4(s)
Silver nitrate and magnesium iodide
Molecular Equation: 2AgNO3(aq) + MgI2(aq) ( 2AgI(s) + Mg(NO3)2(aq)
Complete Ionic Equation: 2Ag+(aq) + 2NO3-(aq) + Mg2+(aq) + 2I-(aq) ( 2AgI(s) + Mg2+(aq) + 2NO3-(aq) Particulate drawing:
Net Ionic Equation: NIE: 2Ag+(aq) + 2I-(aq) ( 2AgI(s)
(your final answer would be: Ag+(aq) + I-(aq) ( AgI(s))
Ammonium chromate and aluminum perchlorate
Molecular Equation: 3(NH4)2CrO4(aq) + 2Al(ClO4)3(aq) ( Al2(CrO4)3(s) + 6NH4ClO4(aq)
Complete Ionic Equation:
6NH4+(aq) + 3CrO42-(aq) + 2Al3+(aq) + 6ClO4-(aq) ( 6NH4+(aq) + 6ClO4-(aq) + Al2(CrO4)3(s)
Particulate drawing:
Net Ionic Equation: 3C2O42-(aq) + 2Al3+(aq) ( Al2(C2O4)3(s)
Nickel nitrate and sodium hydroxide
Molecular Equation: Ni(NO3)2(aq) + 2NaOH(aq) ( Ni(OH)2(s) + 2NaNO3(aq
Complete Ionic Equation:
Ni2+(aq) + 2NO3-(aq) + 2Na+(aq) + 2OH-(aq) ( Ni(OH)2(s) + 2Na+(aq) + 2NO3-(aq)
Particulate drawing:
Net Ionic Equation: Ni2+(aq) + 2OH-(aq) ( Ni(OH)2(s)
Hydrobromic acid and lead II perchlorate
Molecular Equation: 2HBr(aq) + Pb(ClO4)2(aq) ( 2HClO4(aq) + PbBr2(s)
Complete Ionic Equation:
2H+(aq) + 2Br-(aq) + Pb2+(aq) + 2ClO4-(aq) ( 2H+(aq) + 2ClO4-(aq) + PbBr2(s)
Particulate drawing:
Net Ionic Equation: 2Br-(aq) + Pb2+(aq) ( PbBr2(s)
Potassium fluoride and magnesium nitrate
Molecular Equation: 2KF(aq) + Mg(NO3)2(aq) ( 2KNO3(aq) + MgF2(s)
Ionic Equation: 2K+(aq) + 2F-(aq) + Mg2+(aq) + 2NO3-(aq) ( 2K+(aq) + 2NO3-(aq) + MgF2(s)
Particulate drawing:
Net Ionic Equation: 2F-(aq) + Mg2+(aq) ( MgF2(s)
Sodium phosphate and nickel II perchlorate
Molecular Equation: 2Na3PO4(aq) + 3Ni(ClO4)2(aq) ( 6NaClO4(aq) + Ni3(PO4)2(s)
Complete Ionic Equation:
6Na+(aq) 2PO43-(aq) + 3Ni2+(aq) + 6ClO4-(aq) ( 6Na+(aq) + 6ClO4-(aq) + Ni3(PO4)2(s)
Particulate drawing:
Net Ionic Equation: 2PO43-(aq) + 3Ni2+(aq) ( Ni3(PO4)2(s)
Copper II chloride and silver acetate
Molecular Equation: CuCl2(aq) + 2AgC2H3O2(aq) ( Cu(C2H3O2)2(aq) + 2AgCl(s)
Complete Ionic Equation:
Cu2+(aq) + 2Cl-(aq) + 2Ag+(aq) + 2C2H3O2-(aq) ( Cu2+(aq) + 2C2H3O2-(aq) + 2AgCl(s)
Particulate drawing:
Net Ionic Equation: Cl-(aq) + Ag+(aq) ( AgCl(s)
Net Ionic Equation Worksheet - answers
1. , - b p ucuuO &h{3 hU 5CJ OJ QJ \^J aJ #h{3 h{3 6CJ OJ QJ ^J aJ h{3 h{3 CJ OJ QJ ^J aJ &h{3 hU 6CJ OJ QJ ]^J aJ &h{3 h{3 5>*CJ OJ QJ ^J aJ &h{3 hU 5CJ OJ QJ \^J aJ h{3 hU CJ OJ QJ ^J aJ h{3 hU CJ OJ QJ aJ h{3 h( CJ OJ QJ aJ h{3 h+ CJ OJ QJ aJ L j k T Predicting the solubility of ionic compounds gives insight into feasibility of reactions occuring. CuCl2(aq) + 2AgC2H3O2(aq) ( Cu(C2H3O2)2(aq) + 2AgCl(s)
Ionic Equation: Cu2+(aq) + 2Cl-(aq) + 2Ag+(aq) + 2C2H3O2-(aq) ( Cu2+(aq) + 2C2H3O2-(aq) + 2AgCl(s)
NIE: Cl-(aq) + Ag+(aq) ( AgCl(s)
L j v * 5 b . This may seem overwhelming, but I broke it down step by step for you. Calcium chloride reacts with potassium phosphate to form calcium phosphate and potassium chloride. If a product is soluble (aq) in line 2, write the ions that make it up under it with "+" between them. Why Are pH Values Only In A Range Of 0-14? You can predict whether a precipitate will form using a list of solubility rules such as those found in the table below. 2005 - 2023 Wyzant, Inc, a division of IXL Learning - All Rights Reserved, Explanation of Numbers and Math Problems Set 2, The Periodic Chart of Table of the Elements. Lead (II) Nitrate + Sodium Phosphate . Insoluble substances are not separated and these have the symbol (s) written next to them. This type of reaction is called a precipitation reaction, and the solid produced in the reaction is known as the precipitate. What remains is the net ionic equation. #fca_qc_quiz_62696.fca_qc_quiz div.fca_qc_answer_div.fakehover,
)DOt,5smLLk:1d3\zw8I 2NaCl(aq) + Pb(NO3)2(aq) ( PbCl2(s) + 2NaNO3(aq) Ionic Equation: 2Na+(aq) + 2Cl-(aq) + Pb2+(aq) + 2NO3-(aq) ( PbCl2(s) + 2Na+(aq) + 2NO3-(aq) NIE: 2Cl-(aq) + Pb2+(aq) ( PbCl2(s)
2. **Top line is for the reaction in word form, If you are given just the names of the reactants. #fca_qc_quiz_62696.fca_qc_quiz button.fca_qc_button {
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What is the net ionic equation for the reaction between lead nitrate and sodium chloride? To determine whether a product is insoluble, you need to consult a solubility table like the one below: As you can see, lead(II) chloride is insoluble, and is therefore a precipitate that, which means . One of the products of a double replacement reaction must be water, an insoluble gas that bubbles out of solution, or an insoluble precipitate (solid). Lead (II) chloride will precipitate. Na2CO3(aq) + FeCl2(aq) ( FeCO3(s) + 2NaCl(aq) Ionic Equation: 2Na+(aq) + CO32-(aq) + Fe2+(aq) + 2Cl-(aq) ( FeCO3(s) + 2Na+(aq) + 2Cl-(aq) NIE: CO32-(aq) + Fe2+(aq) ( FeCO3(s)
3. Spectator Ion Examples . 9
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Pb(NO3)2 (aq) + MgCl2 (aq) PbCl2 (s) + Mg(NO3)2 (aq) Write the balanced net ionic equation for the reaction. #"Pb(NO"_3)_2("aq")# + #"2HCl"("aq")# #rarr# #"PbCl"_2("s")# + #"2HNO"_3("aq")#, Net Ionic Equation: Net ionic: Pb2+ + 2Cl- PbCl 2 () c. Spectator ions: Li+ and C 2 H 3 O 2-6. sodium phosphate (aq) + chromium (III) chloride (aq) Na 3 PO 4 + CrCl 3 3NaCl + CrPO 4 () a. Played 12 times. (Use the lowest possible coefficients. #fca_qc_quiz_62696.fca_qc_quiz div.fca-qc-back.correct-answer,
Write molecular equation: Pb (NO3)2 (aq) + Na2CO3 (aq) ==> PbCO3 (s) + 2NaNO3 (aq) Step 2. Adding excess solid sodium chloride to a 500 mL sample of . Solution Verified and sodium chloride exists as an aqueous solution. Balance this ionic equation, which models the formation of a silver carbonate precipitate: Ag + (aq) + CO 3 2- . Write molecular equation: write a balanced molecular and net ionic equation for the reaction . You may have seen these solutions labeled with the subscript aq in chemical equations. background-color: #f57484;
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!&}E]#[S?8X9Vv4A*?@y? Regarding our example, KCL will split into K+ and Cl ions, while Pb(NO3)2will break down into Pb2+and 2NO3on the reactant side. ), (They don't actually participate in the reaction. For 3: Nickel (II) chloride and lead(II) nitrate; The chemical equation for the reaction of lead (II) nitrate and nickel (II) chloride is given as: Ionic form of the above equation follows: As, nickel and nitrate ions are present on both the sides of the reaction. 2AgNO3(aq) + MgI2(aq) ( 2AgI(s) + Mg(NO3)2(aq) Ionic Equation: 2Ag+(aq) + 2NO3-(aq) + Mg2+(aq) + 2I-(aq) ( 2AgI(s) + Mg2+(aq) + 2NO3-(aq) NIE: 2Ag+(aq) + 2I-(aq) ( 2AgI(s)
(your final answer would be: Ag+(aq) + I-(aq) ( AgI(s))
12. Thus, the compounds KCL and KNO3are aqueous. background-color: #FFFFFF;
O Pb2+ (aq) + 2NO3 (aq) + 2K* (aq) + 2Cl (aq) PbCl2 (s) + 2 K+ (aq) + 2NO, (aq O Pb (NO3)2 . Step 1. Show the balanced net ionic equation and list spectator ions when a solution of potassium iodide and lead (II) nitrate react to produce a precipitate of lead (II) iodide suspended in a solution of potassium nitrate. To determine whether a product is insoluble, you need to consult a solubility table like the one below: As you can see, lead(II) chloride is insoluble, and is therefore a precipitate that, which means the double replacement reaction does occur.